
Originally Posted by
Stereo
0 6 3 5 5 5 5 ...
1) If the number produces a distinct integer when divided by 2, do that
2) otherwise, count the number of segments the number represents on a 7 segment display, and switch to that number.
I like these rules because despite being over the set of single digit integers, there are 2 stable solutions - 5 maps to itself, and the sequence 2 1 2 1 repeats forever as well.
0: 6 3 5...
1: 2 1 [...]
2: 1 2 [...]
3: 5...
4: 2 1 [...]
5: 5...
6: 3 5...
7: 3 5... | 4 2 1 [...] - depends how you display sevens
8: 4 2 1 [...]
9: 5...
Out of 10 digits, 5 map to one solution, 5 map to the other (if your seven is like '7). awesome.
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