Assume the following:
y = (n * pi) / (n + 1)
Solve for n when y = pi
I ended up with the following:
n = n + 1
So... where did I mess up? It doesn't make sense that 0 = 1, and I don't recall dividing by zero.
Assume the following:
y = (n * pi) / (n + 1)
Solve for n when y = pi
I ended up with the following:
n = n + 1
So... where did I mess up? It doesn't make sense that 0 = 1, and I don't recall dividing by zero.
Originally Posted by FielThat's where you messed up.Originally Posted by Fiel
You assumed that 0 = 1, therefore you got 0 = 1.
Unless you have the information wrong...I'm not sure.
Assuming that y = pi and that y = (n *pi) / (n + 1) you would get:
Code:y = (n * pi) / (n + 1) pi = (n * pi) / (n + 1) pi(n + 1) = n * pi n + 1 = n
http://www.walterzorn.com/grapher/grapher_e.htm
Graphing it finds a horizontal asymptote at y=pi.
:|
Another way of explaining things:
Pi is not an element of the range of this function.
Actually, you could look at that n=n+1, and realize as the absolute value of n gets large, the equation becomes more and mroe true. [ n/(n+1) -> 1]
That would tell you when y=pi, x=+- infinity.
Comon man, that shouldn't be too hard to figure out. Muscle em up!
And what Kaj said ^^
you lie fiel, thats not math i see no numbers just letters.
(hides in the biology corner where letters are words not numbers)
-hides in the chemistry corner where letters are nasty liquids that corrode metal and skin-
-hides in the engineering corner where letters are... wait, pomegranate.-
I'm not sure if I'm understanding this correctly (high school math level sucks) but the way it looks to me it's pretty obvious that (n*pi)/(n+1) can not equal pi because it doesn't matter what n are you multiplying pi with, you will always divide it with a greater number.
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