What's a long?
Binomial distribution is basically Pascal's triangle:
2hkos, or in other words rolling 2 dice with n sides, is
And yes, you'd think that's even simpler. But the trouble happens when you have 3hkos and beyond. Essentially to find 2hko for strafe you have to find 8hko, since there are 8 independent arrows to consider... plus critical/noncritical for all 8 of them. The nested arrays might do the trick, I don't know at this point.
Binomial distribution is basically Pascal's triangle:
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
etc1 1
1 2 1
1 3 3 1
1 4 6 4 1
2hkos, or in other words rolling 2 dice with n sides, is
1
1 2 1
1 2 3 2 1
1 2 3 4 3 2 1
etc.1 2 1
1 2 3 2 1
1 2 3 4 3 2 1
And yes, you'd think that's even simpler. But the trouble happens when you have 3hkos and beyond. Essentially to find 2hko for strafe you have to find 8hko, since there are 8 independent arrows to consider... plus critical/noncritical for all 8 of them. The nested arrays might do the trick, I don't know at this point.