Electric potential

O.k. So, you would need to translate that potential difference (V) into the electrostatic force, which is simply dividing the V by R. Now, you have N/C, and have a charge and mass, so can get the acceleration in the opposite dirrection. I didn't think too much about it, but I guess you would integrate the acceleration equation with respect to time, and go from velocity = infi to v = 0.

Sounds like you know what you are doing at any rate. Good luck!

I was pursuing a more conceptual understanding of potential (essentially just what the heck it is and what does it mean to say something has a specific quantity of potential).
The answer I came up with:

- Electrical object(s) render(s) the space around them "electrical", every point in space where there is "electrical-ness", there is something called "electric potential"
- From Coulomb's law and various other sources, we know that "electrical-ness" gets stronger near the source(s) and dissipates at infinity
- The potential value at every point in space represents the amount of work per unit charge needed to move the test charge from infinity to that position
- Extrapolating that, people refer to "the potential of an object", which isn't supposed to make sense, to refer to the potential value of the point in space which that object occupies.

I still can't be certain with that definition, since it would be impossible to bring any test charge to that point in space, since it is already occupied by the source charge and therefore the work needed to bring a test charge close to it would blow up to infinity.

The whole idea above is elegantly encapsulated in the concept of equipotential


Every point in the 2D surface is given a height (potential at that point) and the height AT the source should be infinity in the z-direction. Obviously it is not (as the problem in OP suggests), so I must still be missing something.