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Quadratic Formula
#4
Let's see if i can do this right...

ax^2+bx+c=0
x^2 + b/a x = -c/a divide by "a"
x^2 + b/a x + ((1/2)(b/a x))^2 = -c/a + ((1/2)(b/a x))^2 completing the square
x^2 + b/a x + b^2/4a^2 = -c/a + b^2/4a^2 simplified
(x^2 + b/2a )^2 = -c/a + b^2/4a^2 Into binomial form (completed square)

x+ b/2a = sqrt(-c/a + b^2/4a^2 ) square root both sides
x= - b/2a + or - sqrt(-c/a + b^2/4a^2 ) move b/a x to other side

x= - b/2a + or - sqrt((-c/a * 4a/4a) + b^2/4a^2 ) common denominator

x= - b/2a + or - (sqrt( b^2 -4ac))/2a simplified

x= (- b + or - sqrt(b^2 - 4ac))/2a simplify more = quadratic formula.

hopefully you can read this... sorry if it is totally incoherent. but i believe that is how it is done... good luck with this =)
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Messages In This Thread
Quadratic Formula - by Hazzy - 2008-07-06, 08:49 PM
Quadratic Formula - by Worthyness - 2008-07-06, 09:27 PM
Quadratic Formula - by Hazzy - 2008-07-06, 09:41 PM
Quadratic Formula - by Worthyness - 2008-07-06, 10:06 PM
Quadratic Formula - by x0xpriestx0x - 2008-07-08, 10:12 PM
Quadratic Formula - by xCenario - 2008-07-09, 09:22 AM
Quadratic Formula - by Hazzy - 2008-07-09, 11:45 AM
Quadratic Formula - by xCenario - 2008-07-10, 02:10 AM
Quadratic Formula - by Worthyness - 2008-07-10, 02:36 AM
Quadratic Formula - by Thunda - 2008-07-10, 05:14 PM
Quadratic Formula - by xCenario - 2008-07-11, 06:16 AM
Quadratic Formula - by Worthyness - 2008-07-11, 08:37 PM
Quadratic Formula - by Trinity - 2008-07-11, 09:40 PM

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