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A Ball accelarating down a hill
#4
Hazzy Wrote:g*sin[arctan(dy/dx)] is the accelaration at any given point... so you would integrate from the initial point to the current point to find the velocity at any given distance x? and again to find the distance it traveled in a certain time...?
I think I just lost myself....
You can only do straight integration/differentiation to convert between displacement, velocity and acceleration when integrating/differentiating with respect to t(ime).

*Edit* Are you trying to find the velocity? Do what was said above. [Image: eq.latex?v=\sqrt%7B2gf(x)%7D]
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Messages In This Thread
A Ball accelarating down a hill - by Hazzy - 2009-10-18, 12:41 PM
A Ball accelarating down a hill - by Shidoshi - 2009-10-18, 12:51 PM
A Ball accelarating down a hill - by Hazzy - 2009-10-18, 01:01 PM
A Ball accelarating down a hill - by Tempus - 2009-10-18, 02:09 PM
A Ball accelarating down a hill - by Hazzy - 2009-10-18, 03:51 PM
A Ball accelarating down a hill - by Tempus - 2009-10-18, 05:02 PM
A Ball accelarating down a hill - by Kalovale - 2009-10-19, 06:31 AM
A Ball accelarating down a hill - by Shidoshi - 2009-10-19, 07:29 AM
A Ball accelarating down a hill - by Tempus - 2009-10-19, 02:01 PM
A Ball accelarating down a hill - by Hazzy - 2009-10-19, 05:58 PM
A Ball accelarating down a hill - by Shidoshi - 2009-10-19, 08:19 PM

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