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Would anyone happen to be good with linear algebra?

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Would anyone happen to be good with linear algebra?
Dusk
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#4
2009-10-15, 02:33 AM
f(x,y,z) is f on the vector [x,y,z], so yeah f([x,y,z]). I think for 2a you have to set up a matrix X times each vector = the resultant vector they give you and solve for that system of equations.
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Would anyone happen to be good with linear algebra? - by Dusk - 2009-10-15, 02:33 AM

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