2009-10-13, 10:13 PM
(This post was last modified: 2009-10-13, 10:25 PM by y0y0y0y0shi0.)
KajitiSouls Wrote:There's a math help thread you know!
Code:(7x-3y)^2-6 = 7
(7x-3y)^2 = 13
7x - 3y = sqrt(13)
-3y = sqrt(13) / (7x)
y = -[sqrt(13) / (21x)]
Shouldn't it be
y = ([sqrt(13)] - 7x)/-3
?
It should go:
Code:
(7x-3y)^2-6 = 7
(7x - 3y)^2 = 13
7x - 3y = sqrt(13)
-3y = sqrt(13) - 7x
y = ([sqrt(13)] - 7x)/-3Since:
7x - 3y = -3y + 7x