2009-02-24, 12:19 AM
Will Wrote:Hi 0-o I need help with another problem.......I was wondering how to graph equations such as this:Graph the equation y = -3. If you can't understand that, think about any value of x, then think about what the equation equals to.
y=-3 for -1 <(or equal to) x < (or equal to) 1
Then "hide" the graph for any value of x that lies outside of the parameters, in your case, -1 <= x <= 1.
Will Wrote:(x-4)^2 + y^2 = 1 for x>31/8
This one is a lot more complicated.
Where I would start is separate the y and x variables, so that they're on the opposite sides of the equal sign. Then figure out for which values of x give you the equation y^2 = 0. Just in case you're wondering, x = 4 does not give you y^2 = 0.
Also, beware that since y is squared, any negative value of y will also work to satisfy any positive value of y. That is, y^2 = (-y)^2.

