Devil's Sunrise Wrote:Wow, impressive grinding skills. I'm gonna start now checking what I can do to get the way out of that maze the fastest way possible. Looking at theories, mainly.

jrvillarreal Wrote:Someone with Photoshop look up "how to solve a maze with photoshop" it's hilariously useful

Screw that. I think my eyes are now bleeding.

xkatiie Wrote:Screw that. I think my eyes are now bleeding.

Rain Wrote:I feel like I just spooned my eyes out looking at it @_@

Bacon Wrote:You guys are nubs. I'll tell you the pro way to solve this maze.

Copy image. Paste into image editting program. Select the 'fill' tool. Choose a different color. Fill in the white.

After you fill everything in, you see that this maze is bogus. You can start anywhere and get anywhere. You can go anywhere in the maze from any starting point. Thanks for wasting a minute of my life.

I'd rather use the fill tool like this:

 OMG spoilers

Fill the part "between" the entrances, and the correct solution will be along the path with one black wall, one red.

Pseudocode for a contiguous fill is not too complex, especially with a 2-color GIF like this where all color matches are exact. Recursively ...

Code:

fill(x,y,newcolor) {
  oldcolor=color(x,y);
  color(x,y) = newcolor;
  for (int i = 0; i<4;i++) {
      if ( color(x+cos(pi/2*i),y+sin(pi/2*i)) == oldcolor ) {
        fill(x+cos(pi/2*i),y+sin(pi/2*i),newcolor);
      }
    }
  }
}

edit: oops

Stereo Wrote:Pseudocode for a contiguous fill is not too complex, especially with a 2-color GIF like this where all color matches are exact. Recursively ...

Code:

fill(x,y,newcolor) {
  oldcolor=color(x,y);
  color(x,y) = newcolor;
  for (int i = 0; i<4;i++) {
      if ( color(x+cos(pi/2*i),y+sin(pi/2*i)) == oldcolor ) {
        fill(x+cos(pi/2*i),y+sin(pi/2*i),newcolor);
      }
    }
  }
}

edit: oops[/color]

 Spoiler