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  1. Default I screwed up math somehow


    Assume the following:

    y = (n * pi) / (n + 1)

    Solve for n when y = pi

    I ended up with the following:

    n = n + 1

    So... where did I mess up? It doesn't make sense that 0 = 1, and I don't recall dividing by zero.

  2. Default


    That's where you messed up.

    You assumed that 0 = 1, therefore you got 0 = 1.

  3. Default


    Unless you have the information wrong...I'm not sure.
    Assuming that y = pi and that y = (n *pi) / (n + 1) you would get:

    Code:
    y = (n * pi) / (n + 1)
    pi = (n * pi) / (n + 1)
    pi(n + 1) = n * pi
    n + 1 = n


  4. Lazy Mathematician Female
    IGN: MsJudith
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    Default


    Another way of explaining things:

    Pi is not an element of the range of this function.

  5. Default


    Actually, you could look at that n=n+1, and realize as the absolute value of n gets large, the equation becomes more and mroe true. [ n/(n+1) -> 1]
    That would tell you when y=pi, x=+- infinity.


  6. Orbital Bee Cannon
    IGN: BuffDaSnail
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    Default


    Comon man, that shouldn't be too hard to figure out. Muscle em up!

    And what Kaj said ^^

  7. Default


    A variable that is approaching a value is not the same as the variable being the value.

  8. Default


    you lie fiel, thats not math i see no numbers just letters.

    (hides in the biology corner where letters are words not numbers)

  9. Default


    -hides in the chemistry corner where letters are nasty liquids that corrode metal and skin-

  10. Heavily armored Humvee
    IGN: TheSovereignBowi
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    Default


    -hides in the engineering corner where letters are... wait, pomegranate.-

  11. Default


    I'm not sure if I'm understanding this correctly (high school math level sucks) but the way it looks to me it's pretty obvious that (n*pi)/(n+1) can not equal pi because it doesn't matter what n are you multiplying pi with, you will always divide it with a greater number.

  12. Default


    That is a correct interpretation if you divide out PI on both sides first.

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