# Thread: I screwed up math somehow

1. ## I screwed up math somehow

Assume the following:

y = (n * pi) / (n + 1)

Solve for n when y = pi

I ended up with the following:

n = n + 1

So... where did I mess up? It doesn't make sense that 0 = 1, and I don't recall dividing by zero.

2. That's where you messed up.

You assumed that 0 = 1, therefore you got 0 = 1.

3. Unless you have the information wrong...I'm not sure.
Assuming that y = pi and that y = (n *pi) / (n + 1) you would get:

Code:
```y = (n * pi) / (n + 1)
pi = (n * pi) / (n + 1)
pi(n + 1) = n * pi
n + 1 = n```

4. http://www.walterzorn.com/grapher/grapher_e.htm
Graphing it finds a horizontal asymptote at y=pi.
:|

5. Another way of explaining things:

Pi is not an element of the range of this function.

6. Actually, you could look at that n=n+1, and realize as the absolute value of n gets large, the equation becomes more and mroe true. [ n/(n+1) -> 1]
That would tell you when y=pi, x=+- infinity.

7. Silly Fiel, learn to recognize asymptotes =P

8. Comon man, that shouldn't be too hard to figure out. Muscle em up!

And what Kaj said ^^

9. A variable that is approaching a value is not the same as the variable being the value.

10. you lie fiel, thats not math i see no numbers just letters.

(hides in the biology corner where letters are words not numbers)

11. -hides in the chemistry corner where letters are nasty liquids that corrode metal and skin-

12. -hides in the engineering corner where letters are... wait, pomegranate.-

13. I'm not sure if I'm understanding this correctly (high school math level sucks) but the way it looks to me it's pretty obvious that (n*pi)/(n+1) can not equal pi because it doesn't matter what n are you multiplying pi with, you will always divide it with a greater number.

14. That is a correct interpretation if you divide out PI on both sides first.

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