in short: crazy man is going to jump 120k feet/36km, just on the border of earths atmosphere.
they are currently rolling out the balloon.
I searched for a thread, no results.
edit: he reached 39 kilometers and a maximum speed of 1172 kmph, which is around 720mph(help here).
2012-10-09, 12:38 PM
Eliseo
Re: TODAY: Redbull Stratos jump!
It's starting!
Hope it ends well.
Edit: Mission Aborted?
2012-10-09, 12:40 PM
KhainiWest
Re: TODAY: Redbull Stratos jump!
I heard about this on the radio, he wants to break the sound barrier or something
edit: 36.5km skydive attempt aborted because of high winds in New Mexico.
2012-10-09, 02:56 PM
Nion
Re: TODAY: Redbull Stratos jump!
Oh god, the past few days has been the craziest. Some guy trying to have that lightning thing through the body thing with chainmail and stuff and this. :goggle:
2012-10-14, 10:38 AM
Link
Re: TODAY: Redbull Stratos jump!
So uh... I'm watching this live on TV. Anyone else?
2012-10-14, 11:22 AM
Mazz
Re: TODAY: Redbull Stratos jump!
Quote:
Originally Posted by Link
So uh... I'm watching this live on TV. Anyone else?
Me too!
Live update: nothing has happened.
edit: it's been an hour. NOTHING HAS HAPPENED
2012-10-14, 12:36 PM
Raph589
Re: TODAY: Redbull Stratos jump!
Only 4k more feets until he jumps.
2012-10-14, 12:41 PM
WubYou4ever
Re: TODAY: Redbull Stratos jump!
Noooo the vid doesn't work, hope everything turn out fine
2012-10-14, 01:17 PM
Marksman Bryan
Re: TODAY: Redbull Stratos jump!
He jumped and landed; free fall for 4:19
2012-10-14, 01:20 PM
byakugan
Re: TODAY: Redbull Stratos jump!
Just found out about this. turned it on, he already landed
Sucks to be me.
2012-10-14, 01:27 PM
OmegazeroGA
Re: TODAY: Redbull Stratos jump!
So he reached 729mph, is that mach?
2012-10-14, 04:06 PM
FoolsLove
Re: TODAY: Redbull Stratos jump!
Quote:
Originally Posted by OmegazeroGA
So he reached 729mph, is that mach?
Close, mach 1 is 768mph.
2012-10-14, 04:39 PM
Malthe
Re: TODAY: Redbull Stratos jump!
Quote:
Originally Posted by FoolsLove
Close, mach 1 is 768mph.
But the higher up you are, the slower sound moves compared to down here at sea level. I'm not sure if he reached Mach 1.
Would require the speed of sound to have been 729 mph where he reached that speed himself.
2012-10-14, 05:29 PM
FoolsLove
Re: TODAY: Redbull Stratos jump!
Apparently he reached 833mph, which is over mach 1.
2012-10-14, 10:27 PM
Locked
Re: TODAY: Redbull Stratos jump!
833.9 mph, Mach 1.24.
2012-10-15, 12:31 PM
Taku
Re: TODAY: Redbull Stratos jump!
only crazy white people will do this pomegranate.
2012-10-15, 12:34 PM
KhainiWest
Re: TODAY: Redbull Stratos jump!
Quote:
Originally Posted by Taku
only crazy white people will do this pomegranate.
Asians genetials are too small to attempt this sh`it.
2012-10-16, 08:44 PM
Shidoshi
He didn't actually do it: Felix Baumgartner's Mach Jump
I've done some calculations and it's impossible for him to have reached even Mach 1.
Assuming constant gravitational acceleration (it varies from 9.81mē/s at sea level to 9.69mē/s at the start of his jump) and no friction.
He fell 119846ft (from 128000ft to 8154ft) in 4min19s = 259seconds.
So his average speed during the fall is Vavg = 36529m/259s = 141.04 m/s
His acceleration during fall is something of the form:
a = C - f(V), where f(V) is an always positive and monotonically increasing function of V that never exceeds C.
By that we can see that v(t) is a monotonically increasing, concave function (its first derivative is positive and its second derivative is negative).
Having that, the highest maximum velocity he could have had at the end of 259 seconds would be if his speed profile, v(t) was a straight line (no friction).
That velocity would be 2*Vavg = 242.08m/s or Mach 0.82
QED
Adding friction to the equation only lowers his maximum speed.
Disclaimer: This doesn't take away from the rest of the records he broke.
2012-10-16, 09:15 PM
VerrKol
Re: He didn't actually do it: Felix Baumgartner's Mach Jump
Quote:
Originally Posted by Shidoshi
I've done some calculations and it's impossible for him to have reached even Mach 1.
Assuming constant gravitational acceleration (it varies from 9.81mē/s at sea level to 9.69mē/s at the start of his jump) and no friction.
He fell 119846ft (from 128000ft to 8154ft) in 4min19s = 259seconds.
So his average speed during the fall is Vavg = 36529m/259s = 141.04 m/s
His acceleration during fall is something of the form:
a = C - f(V), where f(V) is an always positive and monotonically increasing function of V that never exceeds C.
By that we can see that v(t) is a monotonically increasing, concave function (its first derivative is positive and its second derivative is negative).
Having that, the highest maximum velocity he could have had at the end of 259 seconds would be if his speed profile, v(t) was a straight line (no friction).
That velocity would be 2*Vavg = 242.08m/s or Mach 0.82
QED
Adding friction to the equation only lowers his maximum speed.
Disclaimer: This doesn't take away from the rest of the records he broke.
Acceleration isn't uniform here. You can't claim v is linearly proportional to t ergo 2*Vavg=/=Vmax
Even with that brutal approximation he certainly didn't fall straight down. Even a 10 degree deviation would put him over mach 1. /* 36.529/cos(10)=37.1
37.1km/259s=143m/s
143*2=286m/s > mach 1 */
If I get really bored on Friday I'll try to find an estimation for his drag because working out the actual boundary equations would give me a brutal headache. I'm a physicist not an engineer dammit!
2012-10-16, 09:24 PM
Shidoshi
Re: He didn't actually do it: Felix Baumgartner's Mach Jump
Quote:
Originally Posted by VerrKol
Acceleration isn't uniform here. You can't claim v is linearly proportional to t ergo 2*Vavg=/=Vmax
Even with that brutal approximation he certainly didn't fall straight down. Even a 10 degree deviation would put him over mach 1.
***Hidden content cannot be quoted.***
If I get really bored on Friday I'll try to find an estimation for his drag because working out the actual boundary equations would give me a brutal headache. I'm a physicist not an engineer dammit!
I'm not saying his acceleration is actually uniform, only that it sets an upper boundary to his maximum speed.
I hadn't considered the possibility that he'd fall at an angle though, that's an interesting approach.
Mach 1 is actually 343.2 m/s by the way.
Still for him to reach Mach 1.24 the angle would have to be:
2*36529/(259*cos(x)) = 1.24*343.2 => x = 48°
Yeah, he didn't fall at a 48° angle, nope.
/* For Mach 1 you'd still have an angle of nearly 35° which I still severely doubt possible. */